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See also: partition (81X283...) contains a See also: part s
.
Further, if DAiDA2 denote successive operations of DA1 and Da2, Da1Da2(X1a2a2...) _ (X3...),
and the operations are evidently commutative
.
Also DPiDmDPB..•(p;1p2ap33...) =1, and the See also: law of operation of the operators D upon a monomial symmetric See also: function is clear
.
We have obtained the See also: equivalent operations
1+µD1+µ2D2 +µ3D3+
...
=exppol
where exp denotes (by the See also: rule over exp) that the multiplication of operators is symbolic as in See also: Taylor's theorem. d'1 denotes, in fact, an operator of
See also: order s, but we may transform the right-See also: hand See also: side
so that we are only concerned with the successive performance of linear operations
.
For this purpose write
a1 =a°,+a1aa,+1+a2aaa}2+
....
It has been shown (vide " Memoir on Symmetric Functions of the Roots of Systems of Equations," Phil
.
Trans
.
189o, p
.
490) that
exp(midi+m2d2+m3d3+...) =exp(M1d1+M2d2+Msda+...), where now the multiplications on the dexter denote successive operations, provided that
exp(M1f;+M22+M3r,3+...) =1+mlt+mzt;2+mat3+...; being an undetermined algebraic quantity
.
Hence we derive the particular cases
expol = exp(di —zd2+5(13 —...) ;
expadl = exp (µdl -2µ2d2+3µ3d2 —...),
and we can express D. in terms of d1, d2, d3,..., products denoting successive operations, by the same law which expresses the elementary function a, in terms of the sums of See also: powers s1, S2, SS," Further, we can express da in terms of D1, D2, D2, ... by the same law which expresses the power function s, in terms of the elementary functions al, See also: a2, a3,
...
Operation of Da upon a Product of Symmetric Functions.—Suppose f to be a product of symmetric functions flf2.. f
.
If in the identity f =f, See also: f2...fm we introduce a new rootµ we change as into a1+/as—1, and we obtain
(1 +µD1+µ2D2+
...
+µ'Da+...)f
= (1-}-µD1+112D2+.:.+µ'Da+...)f1
X (1 +µD1+µ2D2+...+µ'Da+...) f2 X
.
X (1+11D3+112D2+•••+µ'Da+•••)fm,
and now expanding and equating coefficients of like powers of µ D1f =~(D1f1)f.fa...f
D2f =x(D2f1)f2f3...f +(Dlfl) (D1f2)f3... fm,
D3f =E(D3f1)f2f3...fm+ (D3f1)(Dlf2)f3...fm+(D3f1)f2fs...fm,
the summation in a See also: term covering every distribution of the operators of the type presenting itself in the term
.
Writing these results
D1f = D(nf,
D2f = D(2)f+Du2)f,
D3f = D<3)f+D(21)f+Da3)f,
et
B.,(mµl,mµuemµst, )
1, z, a,
we may write in general
De f =ED(plp2p3e.).f,
the summation being for every partition (plp2p3...) of s, and D(ptp2p3...)f being =E(Dpl.fl)(Dp2.f2)(DP3f3)f+...fm
.
Ex. gr
.
To operate with D2 upon (213)(214)(15), we have
D(2)fy' = (13) (Z14) (15) +(213) (14) (15)
.
Dc12).f = (122) (2P) (15) +(213) (213) (14) +(212) (214) (14),
and hence
D2f = (214) (15) (13) + (213) (15) (14) +(213) (212) (15) + (213)2 (14)
+(214) (212) (14)
.
Application.to Symmetric Function Multiplication.—An example will explain this
.
Suppose we wish to find the coefficient of (52413) in the product (213)(214)(15)
.
Write
(213) (214) (15) _
...
+A(524) (13) +
...
;
D,See also: D2D7(213)(214)(15) =A;
every other term disappearing by the fundamental See also: property of D,
.
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